document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=560647>Question 560647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes Jake, 14h to repair a car’s transmission. After he had worked for 7 h, Alice began to help him. Together, they finished the job in 3 more hours. How long would it take Alice to do the job alone?\r<BR>\n" );
document.write( "\n" );
document.write( "I attempted to do this problem like I did the other one's by assigning a variable to the unknown amout of time worked by Alice. Then I got stuck when I tried to find the rate for both. And I think I'm supposed to subtract somewhere. Any help would be appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363987 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jake had completed half of the job (7/14) when Alice began\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "they each do some fraction of half the job based on their individual rates ___ (3 / 14) + (3 / x) = 1/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiplying by 14x ___ 3x + 42 = 7x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );