document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=560524>Question 560524</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An Angle is 12 degrees less than one half of its supplement. Find the supplement? i need help setting this up. Would it be x + 12 = 1/2(180-x) because i keep getting a decimal on that. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363979 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An Angle is 12 degrees less than one half of its supplement.<BR>\n" );
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document.write( "Your equation: x + 12 = 1/2(180-x) is correct to find the angle x<BR>\n" );
document.write( "x + 12 = 90 - .5x<BR>\n" );
document.write( "x + .5x = 90 - 12<BR>\n" );
document.write( "1.5x = 78<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=78%2F1.5 ALIGN=MIDDLE  ALT=\"78%2F1.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 52 degrees is the angle<BR>\n" );
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document.write( "Find the supplement? 180 - 52 = 128 degrees<BR>\n" );
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document.write( "We can confirm this<BR>\n" );
document.write( "52 + 12 = .5(128)<BR>\n" );
document.write( "64 = 64<BR>\n" );
document.write( " </SPAN>\n" );
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