document.write( "Question 560584: 1. 17 degrees 49 minutes and 10 seconds added to 22 degrees 22 minutes and 59 seconds, equals to?\r
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\n" ); document.write( "\n" ); document.write( "5.64y = 64
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Algebra.Com's Answer #363969 by Edwin McCravy(20063)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "1. 17 degrees 49 minutes and 10 seconds added to 22 degrees 22 minutes and 59 seconds, equals to?
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document.write( "      17°  49'  10\"\r\n" );
document.write( "     +22°  22'  59\" \r\n" );
document.write( "      39°  71'  69\"\r\n" );
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document.write( "Subtract 60\" from 69\" and get 9\".  Add 1' to the 71' and get 72'.\r\n" );
document.write( "So now you have:\r\n" );
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document.write( "      39° 72'  9\"\r\n" );
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document.write( "Next subtract 60' from 72' and get 12'.  Add 1° to the 39° and get 40°.\r\n" );
document.write( "So you end up with\r\n" );
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document.write( "      40° 12'  9\"\r\n" );
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\n" ); document.write( "2. To what power must 10 be raised to equal 100,000?
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document.write( "Count the zeros in 100,000.  There are 5 of them.  Therefore \r\n" );
document.write( "105 = 100,000.  Answer: the fifth power. \r\n" );
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\n" ); document.write( "3. Area of a right circular cone of base radius r, and height l, is
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document.write( "A cone has two dimensions that are both called \"heigths\".  Ususlly l is for the lateral height, and h for the actual height.  So I'm not sure what you mean, since you just said \"height\" but used l.\r\n" );
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document.write( "The lateral surface area of a right circular cone is \"LSA+=+pi%2Ar%2Al\" where \"r\" is the radius of the circle at the bottom of the cone and \"l\" is the lateral height of the cone (given by the Pythagorean theorem \"l=sqrt%28r%B2%2Bh%B2%29\" where \"h\" is the actual height of the cone). The surface area of the bottom circle of a cone is the same as for any circle, \"pi%2Ar%5E2\". Thus the total surface area of a right circular cone is:\r\n" );
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document.write( "\"SA+=+pi%2Ar%5E2+%2B+pi%2Ar%2Al\" or\r\n" );
document.write( "\"SA+=+pi%2Ar%28r+%2B+l%29\"\r\n" );
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document.write( "4.The supplement of 13 degrees is\r\n" );
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document.write( "180° - 13° = 167°\r\n" );
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\n" ); document.write( "5. 64y = 64
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document.write( "Divide both sides by 64\r\n" );
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document.write( "       \"64y%2F64\" = \"64%2F64\"\r\n" );
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document.write( "Cancel the 64's onthe left and divide on the right:\r\n" );
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document.write( "       \"cross%2864%29y%2Fcross%2864%29\" = \"64%2F64\"\r\n" );
document.write( "       \r\n" );
document.write( "or       y = 1      \r\n" );
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document.write( "Edwin
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