document.write( "Question 560066: If I have 6 objects labeled A-F and I need to know how many different combinations that can be made but each combination MUST include object A, how would I figure this out? And the combinations aren't limited to having to have 6 letters...for example, A by itself is a combination. AB, AC,AD, and DA,EA,FA are all combinations. Any help? \n" ); document.write( "
Algebra.Com's Answer #363932 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "Number of combinations having only one object = 1C1 = 1 i.e A\r
\n" ); document.write( "\n" ); document.write( "because every combination must include object A. \r
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\n" ); document.write( "\n" ); document.write( "number of combinations having two objects = 5C1 = 5\r
\n" ); document.write( "\n" ); document.write( "as we have to choose another 1 out of other 5 objects, A has been chosen already.\r
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\n" ); document.write( "\n" ); document.write( "similarly,
\n" ); document.write( "number of combinations having three objects = 5C2 = 10\r
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\n" ); document.write( "\n" ); document.write( "total number of possible combinations = 1 +5C1 + 5C2 + 5C3 +5C4 +5C5\r
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\n" ); document.write( "\n" ); document.write( "if any doubt, feel free to ask....\r
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