document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=560476>Question 560476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangler picture is 5 inches greater than twice the width. If the perimeter is 112 inches, find the dimensions of the frame. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363900 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangler picture is 5 inches greater than twice the width. If the perimeter is 112 inches, find the dimensions of the frame.<BR>\n" );
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document.write( "Let width = x<BR>\n" );
document.write( "Then length = 2x+5<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "112 = 2(2x+5 + x)<BR>\n" );
document.write( "56 = 3x+5<BR>\n" );
document.write( "3x = 51<BR>\n" );
document.write( "x = 17 inches (width)<BR>\n" );
document.write( "2x+5 = 2*17+5 = 39 inches (length)<BR>\n" );
document.write( "=======================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================== </SPAN>\n" );
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