document.write( "Question 560403: 6(x-2)=8(2x+3) \n" ); document.write( "
Algebra.Com's Answer #363892 by kkasko(46)\"\" \"About 
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6(x-2)=8(2x+3)
\n" ); document.write( "Step 1:multiply what is out of the brackets by what is in the brackets.
\n" ); document.write( "6(x-2)=8(2x+3)
\n" ); document.write( "6x-12=16x+24
\n" ); document.write( "Step 2: get x one one side and the integers on the other by doing the inverse of the interger or the variable.
\n" ); document.write( "6x-12=16x+24
\n" ); document.write( "-6x -24. -6x. -24
\n" ); document.write( "-12-24=16x-6x
\n" ); document.write( "Step: 3 subtract -12-24=-36 and 16x-6x =10x
\n" ); document.write( "Step 4: isolate the variable by dividing by the integer for instance 10 in this case
\n" ); document.write( "-36=10x
\n" ); document.write( "/10./10
\n" ); document.write( "x=-3.6
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