document.write( "Question 560431: a plane leaves chicago and flies 750 miles to new york. if it takes 2.5 hours to get to new york against the wind, but only 2 hours to fly back to chicago, what is the plane's rate of speed and what is the wind speed? \n" ); document.write( "

Algebra.Com's Answer #363876 by stanbon(75887) $\"\"$ $\"About$

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a plane leaves chicago and flies 750 miles to new york. if it takes 2.5 hours to get to new york against the wind, but only 2 hours to fly back to chicago, what is the plane's rate of speed and what is the wind speed?
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\n" ); document.write( "Against wind DATA:
\n" ); document.write( "distance = 750 miles ; time = 2.5 hrs ; rate = d/t = 750/2.5 = 300 mph
\n" ); document.write( "----------------------
\n" ); document.write( "With wind DATA:
\n" ); document.write( "distance = 750 miles ; time = 2 hrs ; rate = d/t = 750/2 = 375 mph
\n" ); document.write( "----------------------
\n" ); document.write( "Equations:
\n" ); document.write( "p + c = 375
\n" ); document.write( "p - c = 300
\n" ); document.write( "----
\n" ); document.write( "Add and solve for \"p\":
\n" ); document.write( "2p = 675
\n" ); document.write( "p = 337.5 mph (speed of the plane in still air)
\n" ); document.write( "-------
\n" ); document.write( "Solve for \"c\":
\n" ); document.write( "p + c = 375
\n" ); document.write( "337.5 + c = 375
\n" ); document.write( "c = 37.5 mph (speed of the wind)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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