document.write( "Question 560195: The local train is 25 miles down the track from central station when the express leaves the station. The local train travels at a rate of 50 mi/hr and the express travels at a rate of 80 mi/hr. Let N represent the number of hours since the express train left Central Station.\r
\n" ); document.write( "\n" ); document.write( "Question 1.) Write at expression that represents the express train's distance from Central Station in N hours.\r
\n" ); document.write( "\n" ); document.write( "Question 2.) When will the express train catch up with the local train?
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Algebra.Com's Answer #363849 by ankor@dixie-net.com(22740)\"\" \"About 
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The local train is 25 miles down the track from central station when the express leaves the station.
\n" ); document.write( " The local train travels at a rate of 50 mi/hr and the express travels at a rate of 80 mi/hr.
\n" ); document.write( " Let N represent the number of hours since the express train left Central Station.
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\n" ); document.write( "Question 1.) Write at expression that represents the express train's distance from Central Station in N hours.
\n" ); document.write( "80n
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\n" ); document.write( "Question 2.) When will the express train catch up with the local train?
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\n" ); document.write( "When the express catches up with the local, they will have traveled the same distance
\n" ); document.write( "write a distance equation: dist = = speed * time
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\n" ); document.write( "80n = 50(n + \"50%2F25\")
\n" ); document.write( "80n = 50(n+.5)
\n" ); document.write( "80n = 50n + 25
\n" ); document.write( "80n - 50n = 25
\n" ); document.write( "30n = 25
\n" ); document.write( "n = \"25%2F30\"
\n" ); document.write( "n = \"5%2F6\" hr or 50 minutes to catch up with the local
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\n" ); document.write( "Confirm this by finding the actual distances, they should be the same:
\n" ); document.write( "Local took half hr longer; 8/6 hrs
\n" ); document.write( "\"5%2F6\"*80 = 66.67 mi
\n" ); document.write( "\"8%2F6\"*50 = 66,67 mi
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