document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54113>Question 54113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the total surface area of a square-based pyramid with isosceles triangular faces.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36384 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the total surface area of a square-based pyramid with isosceles triangular faces. <BR>\n" );
document.write( "LET THE SQUARE SIDE = B.....<BR>\n" );
document.write( "LATERAL SURFACE AREA =L.S.A.<BR>\n" );
document.write( "CASE 1 ...........SLANT SIDE IS GIVEN<BR>\n" );
document.write( "LET THE SLANT SIDES OF TRIAGULAR FACES = D<BR>\n" );
document.write( "LATERAL SURFACE AREA = 4 * TRIANGLE AREA =4*0.5*BASE*SLANT HT.<BR>\n" );
document.write( "SLANT HT = SQRT(D^2-B^2/4)<BR>\n" );
document.write( "HENCE L.S.A.= 2*B*SQRT(D^2-B^2/4)<BR>\n" );
document.write( "CASE 2....SLANT HEIGHT IS GIVEN = H<BR>\n" );
document.write( "L.S.A=2BH<BR>\n" );
document.write( "CASE 3.....VERTICAL HEIGHT IS GIVEN...= V SAY<BR>\n" );
document.write( "THEN SLANT HEIGHT = SQRT(V^2+B^2/4)<BR>\n" );
document.write( "L.S.A. = 2*B*SQRT(V^2+B^2/4)\r<BR>\n" );
document.write( "\n" );
document.write( "BASE AREA <BR>\n" );
document.write( "BASE AREA = B^3\r<BR>\n" );
document.write( "\n" );
document.write( "TOTAL SURFACE AREA <BR>\n" );
document.write( "T.S.A. = L.S.A.+B.S.A....FOUND ABOVE </SPAN>\n" );
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