document.write( "Question 560300: Find θ for 0≤θ≤2pie in the following
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document.write( "Cot θ=0.4291 and cos θ<0
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document.write( "Please help \n" );
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Algebra.Com's Answer #363827 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your interval is from 0 radians to 2 * pi radians which is equivalent to: \n" ); document.write( "from 0 degrees to 360 degrees. \n" ); document.write( "first you want to solve for cotangent theta = .4291 \n" ); document.write( "since cotangent theta is equal to 1 / tangent theta, your equation becomes: \n" ); document.write( "1 / tangent theta = .4291 \n" ); document.write( "multiply both sides of this equation by cotangent theta and divide both sides of this equation by .4291 to get: \n" ); document.write( "1 / .4291 = tangent theta. \n" ); document.write( "simplify to get: \n" ); document.write( "tangent theta = 2.331002331 \n" ); document.write( "to find theta, you take the arc tangent of 2.331002331 to get: \n" ); document.write( "theta = 66.78066768 degrees. \n" ); document.write( "that's the value of theta if theta is in the first quadrant. \n" ); document.write( "in the first quadrant, tangent is positive and cosine is positive, so your answer can't be in the first quadrant because cosine theta has to be less than 0 which means cosine theta must be negative. \n" ); document.write( "tangent theta is positive in the first quadrant and in the third quadrant. \n" ); document.write( "cosine theta is negative in the second quadrant and in the third quadrant. \n" ); document.write( "since the third quadrant allows tangent to be positive and cosine to be negative, your answer must be in the third quadrant. \n" ); document.write( "the equivalent angle in the third quadrant that has the same tangent as an angle in the first quadrant would be equal to 180 + 66.78066768 degrees which makes the angle equal to 246.7806677 degrees. \n" ); document.write( "the equivalent angle in radians is equal to 246.7806677 * pi / 180 which is equal to 1.371003709 * pi radians which is equivalent to 4.307135181 radians. \n" ); document.write( "----- \n" ); document.write( "if you had not converted to degrees, but worked in radians from the beginning, you would have done the following: \n" ); document.write( "your interval is from 0 radians to 2 * pi radians. \n" ); document.write( "first you want to solve for cotangent theta = .4291 \n" ); document.write( "since cotangent theta is equal to 1 / tangent theta, your equation becomes: \n" ); document.write( "1 / tangent theta = .4291 \n" ); document.write( "multiply both sides of this equation by cotangent theta and divide both sides of this equation by .4291 to get: \n" ); document.write( "1 / .4291 = tangent theta. \n" ); document.write( "simplify to get: \n" ); document.write( "tangent theta = 2.331002331 \n" ); document.write( "to find theta, you take the arc tangent of 2.331002331 to get: \n" ); document.write( "theta = 1.165542528 radians \n" ); document.write( "that's the value of theta if theta is in the first quadrant. \n" ); document.write( "in the first quadrant, tangent is positive and cosine is positive, so your answer can't be in the first quadrant because cosine theta has to be less than 0 which means cosine theta must be negative. \n" ); document.write( "tangent theta is positive in the first quadrant and in the third quadrant. \n" ); document.write( "cosine theta is negative in the second quadrant and in the third quadrant. \n" ); document.write( "since the third quadrant allows tangent to be positive and cosine to be negative, your answer must be in the third quadrant. \n" ); document.write( "the equivalent angle in the third quadrant that has the same tangent as an angle in the first quadrant would be equal to pi + 1.165542528 radians which makes the angle equal to 4.307135181 radians. \n" ); document.write( "this is equivalent to 1.371003709 * pi radians. \n" ); document.write( "to make this into degrees multiply by 180 and divide by pi to get 246.7806677 degrees.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |