document.write( "Question 53851This question is from textbook Intermediate Algebra
\n" ); document.write( ": My problem is (3/4, 8/3) and (2/5, 2/3.
\n" ); document.write( "I am supposed to find the slope and put the problem into slope intercept form and then into standard form (Ax+By=C).
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Algebra.Com's Answer #36382 by ankor@dixie-net.com(22740)\"\" \"About 
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:
\n" ); document.write( "My problem is (3/4, 8/3) and (2/5, 2/3).
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\n" ); document.write( "I am supposed to find the slope and put the problem into slope intercept form and then into standard form (Ax+By=C).
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\n" ); document.write( "the slope equation: m = \"%28y2+-+y1%29%2F%28x2+-+x1%29\"
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\n" ); document.write( "In this problem x1 = 3/4; y1 = 8/3, x2 = 2/5, y2 = 2/3
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\n" ); document.write( "Let's get rid of these annoying fractions, mult them all by 60, it won't affect the value of the slope
\n" ); document.write( "Then we have x1 = 45, y1 = 160, x2 = 24, y2 = 40\r
\n" ); document.write( "\n" ); document.write( "m = \"%28%2840%29-%28160%29%29%2F%28%2824%29-%2845%29%29\"=\"%28-120%29%2F%28-21%29\"=\"40%2F7\"
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\n" ); document.write( "m = (40/7) x1 = 3/4, y1 = 8/3
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\n" ); document.write( "Substitute in point/slope equation: y - y1 = m(x-x1)
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\n" ); document.write( "y - 8/3 = (40/7)m(x - 3/4)
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\n" ); document.write( "y - 8/3 = (40/7)x - (40/7)(3/4)
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\n" ); document.write( "y - 8/3 = (40/7)x - 120/28
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\n" ); document.write( "y - 8/3 = (40/7)x - 30/7 reduced the fraction
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\n" ); document.write( "y = (40/7)x - 30/7 + 8/3
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\n" ); document.write( "y = (40/7)x - 90/21 + 56/21
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\n" ); document.write( "y = (40/7)x - 34/21; this is the slope/intercept equation (y = mx+b)
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\n" ); document.write( "-21y = -120x + 34; multiplied eq by -21
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\n" ); document.write( "120x - 21y = 34 is the standard form\r
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