document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=560271>Question 560271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to set up word problem:  The measurement of the widthof a rectangle is the length decreased by 7 meters.  The area is 60 square meters.  Find the lenght and the width.  I know the answer but not able to figure out how to set up the formula to get the right answer l= 12m & w= 5m.  Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363799 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length =x<BR>\n" );
document.write( "width = x-7\r<BR>\n" );
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document.write( "Area = 60 m^2\r<BR>\n" );
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document.write( "Area = L*W\r<BR>\n" );
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document.write( "x(x-7)=60<BR>\n" );
document.write( "x^2-7x=60<BR>\n" );
document.write( "x^2-7x-60=0<BR>\n" );
document.write( "x^2-12x+5x-60=0<BR>\n" );
document.write( "x(x-12)+5(x-12)=0<BR>\n" );
document.write( "(x-12)(x+5)=0<BR>\n" );
document.write( "x=12 OR -5<BR>\n" );
document.write( "ignore negative<BR>\n" );
document.write( "so the length = 12 m<BR>\n" );
document.write( "and the width is 7 less<BR>\n" );
document.write( "so width is 5 m </SPAN>\n" );
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