document.write( "Question 559996: a motorboat has a constant speed of 14 miles per hour relative to the water going upstream for 33 miles and then returning. the total trip time was 7 hours. use this information to find the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #363769 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a motorboat has a constant speed of 14 miles per hour relative to the water going upstream for 33 miles and then returning. \n" ); document.write( " the total trip time was 7 hours. use this information to find the speed of the current. \n" ); document.write( ": \n" ); document.write( "Let c = the rate of the current \n" ); document.write( "then \n" ); document.write( "(14-c) = effective speed upstream (in relation to the land) \n" ); document.write( "and \n" ); document.write( "(14+c) = effective speed downstream \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Time upstr + time downstr = 7 hrs \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "Multiply by (14-c)(14+c), results: \n" ); document.write( "33(14+c) + 33(14-c) = 7(14-c)(14+c) \n" ); document.write( ": \n" ); document.write( "462 + 33c + 462 - 33c = 7(196-c^2) \n" ); document.write( ": \n" ); document.write( "924 = 1372 - 7c^2 \n" ); document.write( ": \n" ); document.write( "7c^2 = 1372 - 924 \n" ); document.write( ": \n" ); document.write( "7c^2 = 448 \n" ); document.write( ": \n" ); document.write( "c^2 = \n" ); document.write( "c^2 = 64 \n" ); document.write( "c = \n" ); document.write( "c = 8 mph is the speed of the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if this checks out. Find the actual time of each trip. \n" ); document.write( "33/(14-8) = 5.5 hrs \n" ); document.write( "33/(14+8) = 1.5 hrs \n" ); document.write( "------------------ \n" ); document.write( "total time: 7.0 hrs \n" ); document.write( " |