document.write( "Question 559996: a motorboat has a constant speed of 14 miles per hour relative to the water going upstream for 33 miles and then returning. the total trip time was 7 hours. use this information to find the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #363769 by ankor@dixie-net.com(22740)\"\" \"About 
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a motorboat has a constant speed of 14 miles per hour relative to the water going upstream for 33 miles and then returning.
\n" ); document.write( " the total trip time was 7 hours. use this information to find the speed of the current.
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\n" ); document.write( "Let c = the rate of the current
\n" ); document.write( "then
\n" ); document.write( "(14-c) = effective speed upstream (in relation to the land)
\n" ); document.write( "and
\n" ); document.write( "(14+c) = effective speed downstream
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "Time upstr + time downstr = 7 hrs
\n" ); document.write( "\"33%2F%28%2814-c%29%29\" + \"33%2F%28%2814%2Bc%29%29\" = 7
\n" ); document.write( ";
\n" ); document.write( "Multiply by (14-c)(14+c), results:
\n" ); document.write( "33(14+c) + 33(14-c) = 7(14-c)(14+c)
\n" ); document.write( ":
\n" ); document.write( "462 + 33c + 462 - 33c = 7(196-c^2)
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\n" ); document.write( "924 = 1372 - 7c^2
\n" ); document.write( ":
\n" ); document.write( "7c^2 = 1372 - 924
\n" ); document.write( ":
\n" ); document.write( "7c^2 = 448
\n" ); document.write( ":
\n" ); document.write( "c^2 = \"448%2F7\"
\n" ); document.write( "c^2 = 64
\n" ); document.write( "c = \"sqrt%2864%29\"
\n" ); document.write( "c = 8 mph is the speed of the current
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if this checks out. Find the actual time of each trip.
\n" ); document.write( "33/(14-8) = 5.5 hrs
\n" ); document.write( "33/(14+8) = 1.5 hrs
\n" ); document.write( "------------------
\n" ); document.write( "total time: 7.0 hrs
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