document.write( "Question 560139: check the data for outliers
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document.write( "4, 6, 12, 14, 18, 24, 30, 60\r
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document.write( "A. No outliers exist
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document.write( "B.The value 6 can be considered an outlier
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document.write( "C.The value 60 can be considered an outlier
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document.write( "D.The value 24 can be considered an outlier \n" );
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Algebra.Com's Answer #363719 by Edwin McCravy(20055)  You can put this solution on YOUR website! 4, 6, 12, 14, 18, 24, 30, 60 \n" );
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document.write( "To find any outliers:\r\n" );
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document.write( "1. Find the first and third quartiles:\r\n" );
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document.write( "a. The first quartile:\r\n" );
document.write( "There are 8 data values. 25% of 8 is 2. Since that is a whole\r\n" );
document.write( "number, the first quartile is the mean of the 2nd and 3rd data values.\r\n" );
document.write( "So we average 6 and 12: \r\n" );
document.write( " = = 9\r\n" );
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document.write( "b. The third quartile:\r\n" );
document.write( "There are 8 data values. 75% of 8 is 6. Since that is a whole\r\n" );
document.write( "number, the third quartile is the mean of the 6th and 7th data values.\r\n" );
document.write( "So we average 24 and 30: \r\n" );
document.write( " = = 27\r\n" );
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document.write( "2. Find the IQR or interquartile range by subtracting them:\r\n" );
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document.write( " 27 - 9 = 18 = IQR\r\n" );
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document.write( "3. Calculate the \"fences\" \r\n" );
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document.write( " a. Multiply the IQR by 1.5\r\n" );
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document.write( " 18×1.5 = 27\r\n" );
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document.write( " b. Subtract 27 from the first quartile:\r\n" );
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document.write( " 9 - 27 = -18 = lower fence.\r\n" );
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document.write( " c. Add 27 to the third quartile:\r\n" );
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document.write( " 27 + 27 = 54 = upper fence.\r\n" );
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document.write( "4. Outliers are any values that are below the lower fence or above\r\n" );
document.write( " the upper fence.\r\n" );
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document.write( "There are no values below the lower fence. There is one value\r\n" );
document.write( "above the upper fence, which is 60.\r\n" );
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document.write( "Therefore 60 is the only outlier. \r\n" );
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document.write( "Answer: C\r\n" );
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document.write( "Edwin \n" );
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