document.write( "Question 560125: During the first part of a trip, a canoeist travels 34 miles at a certain speed. The canoeist travels 9 miles on the second part of the trip at a speed 5mph slower. The total time for the trip is 5hrs. What was the speed on each part of the trip? Type an integer or decimal and round to the nearest hundredth. \n" ); document.write( "
Algebra.Com's Answer #363717 by ankor@dixie-net.com(22740)\"\" \"About 
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During the first part of a trip, a canoeist travels 34 miles at a certain speed.
\n" ); document.write( " The canoeist travels 9 miles on the second part of the trip at a speed 5mph slower.
\n" ); document.write( " The total time for the trip is 5hrs. What was the speed on each part of the trip?
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\n" ); document.write( "Let s = the speed on the 1st 34 mi
\n" ); document.write( "then
\n" ); document.write( "(s-5) = speed on the last 9 mi
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
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\n" ); document.write( "fast time + slow time = 5 hrs
\n" ); document.write( "\"34%2Fs\" + \"9%2F%28%28s-5%29%29\" = 5
\n" ); document.write( "multiply by s(s-5), results:
\n" ); document.write( "34(s-5) + 9s = 5s(s-5)
\n" ); document.write( "34s - 170 + 9s = 5s^2 - 25s
\n" ); document.write( "43s - 170 = 5s^2 - 25s
\n" ); document.write( "0 = 5s^2 - 25s - 43s + 170
\n" ); document.write( "A quadratic equation\
\n" ); document.write( "5s^2 - 68s + 170 = 0
\n" ); document.write( "use the quadratic formula to find s:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this problem x=s; a=5; b=-68; c=170
\n" ); document.write( "\"s+=+%28-%28-68%29+%2B-+sqrt%28-68%5E2-4%2A5%2A170+%29%29%2F%282%2A5%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%2868+%2B-+sqrt%284624-3400+%29%29%2F10+\"
\n" ); document.write( ":
\n" ); document.write( "I'll let you do the rest of the math here
\n" ); document.write( "you will get two positive solutions, but only one will make sense
\n" ); document.write( "Check it in the original time equation
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