document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=560127>Question 560127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the tangent line of the curve<BR>\n" );
document.write( "  x^3+y^2=9 at the point P(2,1). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363700 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take derivative of both sides with respect to x.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 3x^2 + 2y\frac{dy}{dx} = 0\"> (note that you need dy/dx after 2y because y is a function of x, in which we use the chain rule).<BR>\n" );
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document.write( "Solving for dy/dx, we get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{dy}{dx} = -\frac{3x^2}{2y}\">\r<BR>\n" );
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document.write( "At x = 2, y = 1, dy/dx = -12/2 = -6. </SPAN>\n" );
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