document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6607>Question 6607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a hard time with Variation, Progression, and Theorems. My question is What is the quotient of \r<BR>\n" );
document.write( "\n" );
document.write( " b^3+4b^2-3b+126<BR>\n" );
document.write( "------------------ =?<BR>\n" );
document.write( "        b+7\r<BR>\n" );
document.write( "\n" );
document.write( "I have tried to do this question on my own and I am not having any luck, Can someone help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3637 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28b%5E3%2B4b%5E2-3b%2B126%29%2F%28b%2B7%29 ALIGN=MIDDLE  ALT=\"%28b%5E3%2B4b%5E2-3b%2B126%29%2F%28b%2B7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So, use long division..i shall try to write this down here:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "b+7 | <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3%2B4b%5E2-3b%2B126 ALIGN=MIDDLE  ALT=\"b%5E3%2B4b%5E2-3b%2B126\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "First... how many times does b go into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3 ALIGN=MIDDLE  ALT=\"b%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" >? Answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2 ALIGN=MIDDLE  ALT=\"b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > times. So write <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2 ALIGN=MIDDLE  ALT=\"b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > over the cube term.\r<BR>\n" );
document.write( "\n" );
document.write( "Now, multiply the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2 ALIGN=MIDDLE  ALT=\"b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > by both b and 7 and write those answers under, as:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "b+7 | <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3%2B4b%5E2-3b%2B126 ALIGN=MIDDLE  ALT=\"b%5E3%2B4b%5E2-3b%2B126\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "____<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3%2B7b%5E2 ALIGN=MIDDLE  ALT=\"b%5E3%2B7b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now subtract <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3%2B7b%5E2 ALIGN=MIDDLE  ALT=\"b%5E3%2B7b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > from <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3%2B4b%5E2-3b%2B126 ALIGN=MIDDLE  ALT=\"b%5E3%2B4b%5E2-3b%2B126\"   DISABLED_style= \"max-width:90%; height:auto;\" >, to give:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "b+7 | <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3%2B4b%5E2-3b%2B126 ALIGN=MIDDLE  ALT=\"b%5E3%2B4b%5E2-3b%2B126\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "____<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3%2B7b%5E2 ALIGN=MIDDLE  ALT=\"b%5E3%2B7b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "____________________________<BR>\n" );
document.write( "_____<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3b%5E2-3b%2B126 ALIGN=MIDDLE  ALT=\"-3b%5E2-3b%2B126\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now repeat the process..how many times does b go into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3b%5E2 ALIGN=MIDDLE  ALT=\"-3b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >? answer is -3b times...put this on top, then multiply that by both b and 7 and put the answer under. Subtract to leave 18b+126.\r<BR>\n" );
document.write( "\n" );
document.write( "Now repeat the process..how many times does b go into 18b? answer is 18 times...put this on top, then multiply that by both b and 7 and put the answer under. Subtract to leave 0. This means that b+7 divides into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E3%2B4b%5E2-3b%2B126 ALIGN=MIDDLE  ALT=\"b%5E3%2B4b%5E2-3b%2B126\"   DISABLED_style= \"max-width:90%; height:auto;\" > exactly, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+-+3b+%2B+18 ALIGN=MIDDLE  ALT=\"b%5E2+-+3b+%2B+18\"   DISABLED_style= \"max-width:90%; height:auto;\" > times.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "jon.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );