document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=559791>Question 559791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angels are complementary. The sum measures of the first angel and half of the second angel is 64 degrees. find the measurments of angels. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363666 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two angels are complementary.<BR>\n" );
document.write( "A + B = 90\r<BR>\n" );
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document.write( " The sum measures of the first angel and half of the second angel is 64 degrees.<BR>\n" );
document.write( "A + .5B = 64<BR>\n" );
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document.write( "Subtract the 2nd eq from the 1st eq:<BR>\n" );
document.write( "A + B = 90<BR>\n" );
document.write( "A +.5B =64<BR>\n" );
document.write( "------------subtraction eliminates A, find B<BR>\n" );
document.write( ".5B = 26<BR>\n" );
document.write( "B = 2*26<BR>\n" );
document.write( "B = 52 degrees<BR>\n" );
document.write( "then<BR>\n" );
document.write( "A = 90 - 52<BR>\n" );
document.write( "A = 38 degrees<BR>\n" );
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document.write( "Check this<BR>\n" );
document.write( "38 + .5(52) = 64\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );