document.write( "Question 560076: I have word problems using d=r*t. I need help with putting the numbers and variables in the right spots to make an equation. After I figure out how to set up the equation, then I am able to solve the equation.
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document.write( "I need help setting up the equation.\r
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document.write( "Here is the story problem.\r
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document.write( "A person can drive from town A to town B at a certain rate of speed in 5 hours. If he increases his speed by 15kph, he can make the trip in 4 hours. How far is it from town A to town B? I made a table below but I'm not sure if everything is in the right spots.\r
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document.write( " Time * Speed = Distance
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document.write( "Town A S D\r
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document.write( "Town B 5 15 D\r
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document.write( "Length 4 \n" );
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Algebra.Com's Answer #363653 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! I have word problems using d=r*t. I need help with putting the numbers and variables in the right spots to make an equation. After I figure out how to set up the equation, then I am able to solve the equation. \n" ); document.write( "I need help setting up the equation.\r \n" ); document.write( "\n" ); document.write( "Here is the story problem.\r \n" ); document.write( "\n" ); document.write( "A person can drive from town A to town B at a certain rate of speed in 5 hours. If he increases his speed by 15kph, he can make the trip in 4 hours. How far is it from town A to town B? I made a table below but I'm not sure if everything is in the right spots. \n" ); document.write( " \r\n" ); document.write( "We are dealing with the two trips, (not \"the two towns\"). \r\n" ); document.write( "One trip is at a slower speed and the other is at a faster speed.\r\n" ); document.write( "Here is the chart you want to make:\r\n" ); document.write( "\r\n" ); document.write( " Time * Speed = Distance\r\n" ); document.write( "At slower speed \r\n" ); document.write( "At faster speed \r\n" ); document.write( " \n" ); document.write( ">>...A person can drive from town A to town B at a certain rate of speed in 5 hours...<< \r\n" ); document.write( "We let the first (slower) speed be S\r\n" ); document.write( "We let the distance be D\r\n" ); document.write( "We are given that the time is 5 hours, so we fill in the first line:\r\n" ); document.write( "\r\n" ); document.write( " Time * Speed = Distance\r\n" ); document.write( "At slower speed 5 S D \r\n" ); document.write( "At faster speed \r\n" ); document.write( " \n" ); document.write( ">>...If he increases his speed by 15kph, he can make the trip in 4 hours...<< \n" ); document.write( " \r\n" ); document.write( "To get the faster speed we add 15 kph to S, and that is S+15\r\n" ); document.write( "The distance is the same, so it is still D\r\n" ); document.write( "We are given that the time is 4, so we fill in the second line:\r\n" ); document.write( "\r\n" ); document.write( " Time * Speed = Distance\r\n" ); document.write( "At slower speed 5 S D \r\n" ); document.write( "At faster speed 4 S+15 = D\r\n" ); document.write( "\r\n" ); document.write( "That gives us two equations in D and S:\r\n" ); document.write( "\r\n" ); document.write( " 5S = D\r\n" ); document.write( " 4(S+15) = D\r\n" ); document.write( "\r\n" ); document.write( "Since both equal to D, they are equal to each other:\r\n" ); document.write( "\r\n" ); document.write( " 5S = 4(S+15)\r\n" ); document.write( " 5S = 4S + 60\r\n" ); document.write( " S = 60\r\n" ); document.write( "\r\n" ); document.write( "So his slower speed is 60 kph (and his faster speed is 15kph faster or 75kph) \r\n" ); document.write( "\r\n" ); document.write( "To find the distance we substitute 60 for S in 5S = D\r\n" ); document.write( "\r\n" ); document.write( " 5S = D\r\n" ); document.write( " 5(60) = D\r\n" ); document.write( " 300 = D \r\n" ); document.write( "\r\n" ); document.write( "Therefore the distance is 300 kilometers.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |