document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=559965>Question 559965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two complementary angles differ by 18 degrees. find the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363589 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angles add up to 90.<BR>\n" );
document.write( "We have two angles the larger and the smaller. <BR>\n" );
document.write( "l-18=s<BR>\n" );
document.write( "and <BR>\n" );
document.write( "l+s=90\r<BR>\n" );
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document.write( "Since l-18=s we can sub in l-18 for s\r<BR>\n" );
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document.write( "l+l-18=90<BR>\n" );
document.write( "2l=108<BR>\n" );
document.write( "l=54\r<BR>\n" );
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document.write( "sub 54 in for l\r<BR>\n" );
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document.write( "54-18=s<BR>\n" );
document.write( "s=36<BR>\n" );
document.write( " </SPAN>\n" );
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