document.write( "Question 559917: The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width? \n" ); document.write( "
Algebra.Com's Answer #363581 by bluemockingjay7(41)\"\" \"About 
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l = 3w
\n" ); document.write( "w = w
\n" ); document.write( "p= x at most 112\r
\n" ); document.write( "\n" ); document.write( "3w + w < 112 (ill represent it in < )
\n" ); document.write( "2(3w + w) < 112
\n" ); document.write( "6w + 2w < 112
\n" ); document.write( "8w < 112
\n" ); document.write( "8w/8 < 112/8
\n" ); document.write( "w < 14\r
\n" ); document.write( "\n" ); document.write( "the width must be at most 14. (14, 13, 12, 11, 10....)\r
\n" ); document.write( "\n" ); document.write( "greatest possible value = 14
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