document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=559928>Question 559928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve the problem: Pure tin was mixed with an 8% tin alloy to produce an alloy that was 25% tin. How much pure tin and how much 8% alloy were used to produce 184kg of 25% alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363577 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me solve the problem: Pure tin was mixed with an 8% tin alloy to produce an alloy that was 25% tin. How much pure tin and how much 8% alloy were used to produce 184kg of 25% alloy?<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=amt of pure tin used in mixture (kg)<BR>\n" );
document.write( "184-x=amt of 8% tin used in mixture (kg)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "100%x+8%(184-x)=25%*184<BR>\n" );
document.write( "x+14.72-.08x=46<BR>\n" );
document.write( ".92x=46-14.72=31.28<BR>\n" );
document.write( "x=31.28/.92=34<BR>\n" );
document.write( "184-x=150<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "amt of pure tin used in mixture=34 kg<BR>\n" );
document.write( "amt of 8% tin used in mixture=150 kg </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );