document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=559574>Question 559574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is this even considered to be a quadratic equation?? I do not understand by what they mean to solve this.. Do they mean distribute and then solve? But how? Please help! I am very frustrated! Thanks!\r<BR>\n" );
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document.write( "(x-3)(5x+2)= -13(x-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363564 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The other tutor missed the solution x = 3 (since he divided by x-3, assuming it wasn't equal to 0).\r<BR>\n" );
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document.write( "One way to do it is to claim that x = 3 works (which it does). If x is *not* equal to 3, then you may divide both sides by x-3 to obtain the other solution, x = -3. </SPAN>\n" );
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