document.write( "Question 559671: write a rule for linear functions with graphs containing the foollowing pairs of points.
\n" ); document.write( "(-6,4) and (3,-8) \n" ); document.write( "

Algebra.Com's Answer #363495 by Earlsdon(6294) $\"\"$ $\"About$

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You could write the rule in the form of a \"slope-intercept\" linear equation: $\"y+=+mx%2Bb\"$ by finding the slope;
\n" ); document.write( " $\"m+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"$ Use the x- and y-coordinates of the two given points (-6, 4) and (3, -8) as the inputs.
\n" ); document.write( " $\"m+=+%28-8-4%29%2F%283-%28-6%29%29\"$
\n" ); document.write( " $\"m+=+%28-12%29%2F9\"$
\n" ); document.write( " $\"m+=+-4%2F3\"$ so you have:
\n" ); document.write( " $\"y+=+%28-4%2F3%29x%2Bb\"$ To find b, substitute the x- and y-coordintes from either one of the given points. Say (3, -8).
\n" ); document.write( " $\"-8+=+%28-4%2F3%29%2A3%2Bb\"$
\n" ); document.write( " $\"-8+=+-4%2Bb\"$ Add 4 to both sides.
\n" ); document.write( " $\"-4+=+b\"$ now you write the finished equation (rule):
\n" ); document.write( " $\"y+=+%28-4%2F3%29x-4\"$ \n" ); document.write( "

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