document.write( "Question 54089: $\"+abs%28x+-+%28y+-+z%29%29+-+abs%28%28x+-+y%29+-+z%29+=+0+\"$ Solve for X
\n" ); document.write( "I think there is more than one answer on this problem. \n" ); document.write( "

Algebra.Com's Answer #36349 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+abs%28x+-+%28y+-+z%29%29+-+abs%28%28x+-+y%29+-+z%29+=+0+\"$
\n" ); document.write( " $\"+abs%28x+-+%28y+-+z%29%29+=+abs%28%28x+-+y%29+-+z%29+\"$
\n" ); document.write( " $\"+x+-+%28y+-+z%29+=+%28x+-+y%29+-+z+\"$
\n" ); document.write( " $\"+x+-+y+%2B+z+=+x+-+y+-+z+\"$
\n" ); document.write( " $\"+2z+=+0+\"$ so $\"z+=+0\"$
\n" ); document.write( "Since $\"x\"$ and $\"y\"$ cancel each other out, they can be any real value. On the other hand, $\"z\"$ must equal zero. \n" ); document.write( "

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