document.write( "Question 54033This question is from textbook algebra and trigonomerty structure and method - book 2
\n" ); document.write( ": find eqation in standard of the lines through ponit P that are (a) parallel to , and (b)perpendicular to , line L.
\n" ); document.write( "P(2,0); L: x+2y=3
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Algebra.Com's Answer #36347 by funmath(2933)\"\" \"About 
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P(2,0);L(x+2y=3)
\n" ); document.write( "First put L in slope intercept form:\"highlight%28y=mx%2Bb%29\"; m=slope; (0,b)=y-intercept
\n" ); document.write( "\"x%2B2y=3\"
\n" ); document.write( "\"-x%2Bx%2B2y=-x%2B3\"
\n" ); document.write( "\"2y=-x%2B3\"
\n" ); document.write( "\"2y%2F2=-x%2F2%2B3%2F2\"
\n" ); document.write( "\"y=%28-1%2F2%29x%2B3%2F2\"
\n" ); document.write( "L has a slope of -1/2.
\n" ); document.write( "(a)Parallel lines have the same slopes, so the new line has a slope of -1/2 also.P(2,0)=(x1,y1)
\n" ); document.write( "Use the point slope formula \"highlight%28y-y1=m%28x-x1%29%29\" to find the equation of the line:
\n" ); document.write( "\"y-0=-1%2F2%28x-2%29\"
\n" ); document.write( "\"highlight%28y=%28-1%2F2%29x%2B1%29\"
\n" ); document.write( "(b) Perpendicular lines have slopes that are negative reciprocals of each other. So flip -1/2 over and change the sign and your new line will have a slope m=2/1 or m=2. P(2,0) Use the point slope formula to find the equation of the line again.
\n" ); document.write( "\"y-0=2%28x-2%29\"
\n" ); document.write( "\"highlight%28y=2x-4%29\"
\n" ); document.write( "Happy Calculating!!!
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