document.write( "Question 559518: If $\"+log%28+a%2C+x+%29+=+P+\"$ and $\"+log%28+a%2C+y+%29+=+7+\"$ . Express $\"+log%28+a%2C+x%5E2y+%29+\"$ in terms of P and 7.
\n" ); document.write( " $\"+log%28+a%2C+x+%29+=+P+\"$ => $\"+a%5EP+=+x+\"$
\n" ); document.write( " $\"+log%28+a%2C+y+%29+=+7+\"$ => $\"+a%5E7+=+7+\"$
\n" ); document.write( "Log(a,(a^P)^2a^7 ) => Log( a, a^2Pa^7 )
\n" ); document.write( "and I was stuck. I am not even sure of what i'm doing ????
\n" ); document.write( "So, please help.
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Algebra.Com's Answer #363453 by Theo(13342) $\"\"$ $\"About$

You can put this solution on YOUR website!
your problem states:
\n" ); document.write( "log(a,x) = p
\n" ); document.write( "log(a,y) = 7
\n" ); document.write( "you want to express log(a,x^2*y) in terms of p and 7.
\n" ); document.write( "start with log(a,x^2*y)
\n" ); document.write( "this becomes:
\n" ); document.write( "log(a,x^2) + log(a,y) which becomes:
\n" ); document.write( "2*log(a,x) + log(a,y)
\n" ); document.write( "since log(a,x) = p and log(a,y) = 7, your equation becomes:
\n" ); document.write( "2*p + 7
\n" ); document.write( "it can also be shown as:
\n" ); document.write( "2p + 7
\n" ); document.write( "the logarithm rules you are using are:
\n" ); document.write( "log(x*y) = log(x) + log(y)
\n" ); document.write( "log(x^y) = y*log(x)
\n" ); document.write( "these rules apply regardless of the base of the logarithm that is being used.
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