document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=559437>Question 559437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectanlge is 50 feet. the length is 5 more than the width. find the area of the rectangle\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363416 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width =x<BR>\n" );
document.write( "length = x+5\r<BR>\n" );
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document.write( "perimeter = 2*(L+W)\r<BR>\n" );
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document.write( "=2(x+x+5)<BR>\n" );
document.write( "=2(2x+5)<BR>\n" );
document.write( "=4x+10\r<BR>\n" );
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document.write( "4x+10=50<BR>\n" );
document.write( "4x=50-10<BR>\n" );
document.write( "4x=40<BR>\n" );
document.write( "/4<BR>\n" );
document.write( "x=10 feet the width<BR>\n" );
document.write( "length = 10 +5 = 15 ft\r<BR>\n" );
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document.write( "Area = L*W\r<BR>\n" );
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document.write( "=10*15= 150 sq. ft </SPAN>\n" );
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