document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=559425>Question 559425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need some help.  It simply says find the solutions but I am not sure what method it is asking me to solve it with.  I don't know if it means solve using the quadratic equation or if there is some other way I am suppose to be doing it.  Please help! Thanks.\r<BR>\n" );
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document.write( "Find the solutions:\r<BR>\n" );
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document.write( "4)	(m+3)^2 + 5(m+3) –14 = 0<BR>\n" );
document.write( "5)	(2x-1)^2 –4(2x-1) + 2 = 0\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363408 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (m+3)^2 + 5(m+3) –14 = 0\r<BR>\n" );
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document.write( "using the quadratic eqaution \r<BR>\n" );
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document.write( "(m+3)^2+7(m+3)-2(m+3)-14=0\r<BR>\n" );
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document.write( "(m+3)(m+3+7)-2(m+3+7)=0\r<BR>\n" );
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document.write( "(m+3)(m+10)-2(m+10)=0\r<BR>\n" );
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document.write( "(m+10)(m+3-2)=0<BR>\n" );
document.write( "(m+10)(m+1)=0<BR>\n" );
document.write( "m=-10 OR -1<BR>\n" );
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