document.write( "Question 559330: if helen can ride 15km on her bike in the same time it takes her to walk 6km. If her rate riding is 6km/h faster than her rate walking how fast does she walk? \n" ); document.write( "
Algebra.Com's Answer #363383 by mananth(16946)![]() ![]() You can put this solution on YOUR website! walking speed = x km/h \n" ); document.write( "riding speed = x+6 km/h\r \n" ); document.write( "\n" ); document.write( "distance riding = 15 \n" ); document.write( "and \n" ); document.write( "distance walking = 6\r \n" ); document.write( "\n" ); document.write( "time riding = 15/(x+6) \n" ); document.write( "time walking = 6/x\r \n" ); document.write( "\n" ); document.write( "both are same\r \n" ); document.write( "\n" ); document.write( "6/x = 15/(x+6) \n" ); document.write( "cross multiply \n" ); document.write( "6(x+6)=15x \n" ); document.write( "6x+36=15x \n" ); document.write( "9x=36 \n" ); document.write( "/9 \n" ); document.write( "x=4 \n" ); document.write( "walking speed = 4km/h \n" ); document.write( "riding speed = 6+4 = 10 km/h \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |