document.write( "Question 559361: Solve (2x+5)(6x-1)=120 \n" ); document.write( "

Algebra.Com's Answer #363382 by mananth(16946) $\"\"$ $\"About$

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(2x+5)(6x-1)=120\r
\n" ); document.write( "\n" ); document.write( "2x(6x-1)+5(6x-1)=120\r
\n" ); document.write( "\n" ); document.write( "12x^2-2x+30x-5=120
\n" ); document.write( "12x^2+28x-5-120=0
\n" ); document.write( "12x^2+28x-125=0\r
\n" ); document.write( "\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 12 , b= 28 , c= -25
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\n" ); document.write( "b^2-4ac= 784 + 1200
\n" ); document.write( "b^2-4ac= 1984
\n" ); document.write( " $\"%09sqrt%28%091984%09%29=%0944.54%09\"$
\n" ); document.write( " $\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( " $\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( "x1=( -28 + 44.54 )/ 24
\n" ); document.write( "x1= 0.69
\n" ); document.write( "x2=( -28 -44.54 ) / 24
\n" ); document.write( "x2= -3.02
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