document.write( "Question 559338: Could you help me solve the equation of $\"++x%5E2%2B12x=15++\"$ \n" ); document.write( "

Algebra.Com's Answer #363364 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"++x%5E2%2B12x+=+15++\"$
\n" ); document.write( "You can solve by completing the square.
\n" ); document.write( "Take 1/2 of the coefficient of $\"x\"$ ,
\n" ); document.write( "square it, and add it to both sides
\n" ); document.write( " $\"+x%5E2+%2B+12x+%2B+%2812%2F2%29%5E2+=+15+%2B+%2812%2F2%29%5E2+\"$
\n" ); document.write( " $\"+x%5E2+%2B+12x+%2B+36+=+15+%2B+36+\"$
\n" ); document.write( " $\"+%28+x+%2B+6+%29%5E2+=+51+\"$
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( " $\"+x+%2B+6+=+sqrt%28+51+%29+\"$
\n" ); document.write( " $\"+x+=+sqrt%2851%29+-+6+\"$
\n" ); document.write( "and also, taking the negative square root,
\n" ); document.write( " $\"+x+=+-sqrt%2851%29+-+6+\"$
\n" ); document.write( "------------------
\n" ); document.write( "I will attempt to check the 1st solution
\n" ); document.write( " $\"+%28+sqrt%2851%29+-+6%29%5E2%2B12%2A%28+sqrt%2851%29+-+6%29+=+15+\"$
\n" ); document.write( " $\"+51+-+12%2Asqrt%2851%29+%2B+36+%2B+12%2Asqrt%2851%29+-+72+=+15+\"$
\n" ); document.write( " $\"+51+%2B+36+-+72+=+15+\"$
\n" ); document.write( " $\"+15+=+15+\"$
\n" ); document.write( "OK
\n" ); document.write( "You can check the other solution, $\"+x+=+-sqrt%2851%29+-+6+\"$ \n" ); document.write( "

\n" );