document.write( "Question 559244: you go to a game show and the prze at the end is a case full of $10 and $20 bills. The hosts tells you there are 400 bills in the case totaling $6,250. To win you have to figure out how many 10 and 20 $ bills are in the case. \n" ); document.write( "

Algebra.Com's Answer #363351 by Edwin McCravy(20060) $\"\"$ $\"About$

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you go to a game show and the prze at the end is a case full of $10 and $20
\n" ); document.write( "bills. The hosts tells you there are 400 bills in the case totaling $6,250. To
\n" ); document.write( "win you have to figure out how many 10 and 20 $ bills are in the case.
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document.write( "This can be solved with or without using algebra.  I'll do it both ways:\r\n" );
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document.write( "1. Without algebra:\r\n" );
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document.write( "If all 400 bills were tens, there would be only $4000, which would be\r\n" );
document.write( "$2250 short, so 225 of the bills must be worth an extra $10 to make it\r\n" );
document.write( "worth $6250.  So there nust be 225 twenties and the rest (175) tens.  \r\n" );
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document.write( "2. With algebra:\r\n" );
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document.write( "Let x = the number of tens and  y = the number of twenties\r\n" );
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document.write( "               x +   y =  400  <-- the bill equation\r\n" );
document.write( "             10x + 20y = 6250  <-- the money equation \r\n" );
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document.write( "Solve that by substitution and get x=175 tens, y = 225 twenties.\r\n" );
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document.write( "Edwin

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