document.write( "Question 559245: Danny invested some money at 3% simple interest and some money at 7% simple interest. The amount invested at the higher rate was $3,000 more than the amoung invested at the lower rate. If the total interest on the investments for 1 year was $810, then how much did he invest at each rate. \n" ); document.write( "

Algebra.Com's Answer #363345 by mananth(16946) $\"\"$ $\"About$

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Amount @ 3.00% x
\n" ); document.write( "Amount @ 7.00% x + 3000
\n" ); document.write( "Total interest earned = 810
\n" ); document.write( "
\n" ); document.write( "3.00% x+ 7.00%(x +3000 )= 810
\n" ); document.write( "3.00% x+7.00% *x+210= 810
\n" ); document.write( "3.00% x+0.07x +210=810
\n" ); document.write( "0.03x-0.07x= 600
\n" ); document.write( "0.1 x = 600
\n" ); document.write( " x= 6000 Amount @ 3.00%
\n" ); document.write( "
\n" ); document.write( "Amount @7.00%= 6000 + 3000
\n" ); document.write( " = 9000
\n" ); document.write( "
\n" ); document.write( "= 0
\n" ); document.write( "CHECK
\n" ); document.write( "6000 @ 3.00% = 180
\n" ); document.write( "9000 @ 7.00% = 630
\n" ); document.write( "
\n" ); document.write( "Total income = 810
\n" ); document.write( "m.ananth@hotmail.ca
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