document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=559233>Question 559233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line that passes through the point (5, 4) and is perpendicular to the line<BR>\n" );
document.write( "2x + 3y &#8722; 6 = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363329 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for a perpendicular equation; swap the x and y coefficients and change one of the signs<BR>\n" );
document.write( "___ this changes the slope to the negative reciprocal\r<BR>\n" );
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document.write( "to pass through a given point; substitute the coordinates into the equation and find the new constant term\r<BR>\n" );
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document.write( "3x - 2y + ? = 0 ___ substituting ___ 3(5) - 2(4) + ? = 0 ___ ? = -7\r<BR>\n" );
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document.write( "3x - 2y - 7 = 0 </SPAN>\n" );
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