document.write( "Question 559201: Line two is perpendicular to 3x-12y=24 and passes through the point (2,-5). Find an equation for line two. (Use the slope of line two).\r
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\n" ); document.write( "\n" ); document.write( "I have worked this problem by finding the slope of 3x-12y=24, which is 1/4. Also, the perpendicular line (line two) has a slope of -4. I am just a little stumped on how to Find an equation that passes through the point (2,-5). Please help.
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Algebra.Com's Answer #363325 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
ONE WAY
\n" ); document.write( "You could do it by writing the equation of the line in point-slope form, using the coordinates of the point given:
\n" ); document.write( "\"y-%28-5%29=-4%28x-2%29\"
\n" ); document.write( "and then you could work with it to transform it into an equivalent expression that looks more elegant, like this:
\n" ); document.write( "\"y-%28-5%29=-4%28x-2%29\" --> \"y%2B5=-4x%2B8\" --> \"y=-4x%2B8-5\" --> \"y=-4x%2B3\"
\n" ); document.write( "or \"y-%28-5%29=-4%28x-2%29\" --> \"y%2B5=-4x%2B8\" --> \"4x%2By%2B5=8\" --> \"4x%2By=3\"
\n" ); document.write( "ANOTHER WAY
\n" ); document.write( "You could also write the slope-intercept form of a line with slope \"-4\" as
\n" ); document.write( "\"y=-4x%2Bb\" and find \"b\" by substituting the coordinates of the point and solving for \"b\"
\n" ); document.write( "\"-5=-4%2A2%2Bb\" --> \"-5=-8%2Bb\" --> \"-5%2B8=b\" --> \"b=3\"
\n" ); document.write( "So you get \"y=-4x%2B3\".
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