document.write( "Question 559127: how do you solve (x+2)^2/9- (y+8)^2/4= 1 \n" ); document.write( "
Algebra.Com's Answer #363323 by lwsshak3(11628)\"\" \"About 
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how do you solve (x+2)^2/9- (y+8)^2/4= 1
\n" ); document.write( "This is an equation for a hyperbola with horizontal transverse axis of the standard form:
\n" ); document.write( "(x-h)^/a^2-(y-k)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.
\n" ); document.write( "..
\n" ); document.write( "For given equation:
\n" ); document.write( "center: (-2,-8)
\n" ); document.write( "a^2=9
\n" ); document.write( "a=√9=3
\n" ); document.write( "b^2=4
\n" ); document.write( "b=√4=2
\n" ); document.write( "c^2=a^2+b^2=9+4=13
\n" ); document.write( "c=√13≈3.6
\n" ); document.write( "Vertices: (-2±a,-8)=(-2±3,-8)=(-5,-8) and (1,-8)
\n" ); document.write( "Foci: (-2±c,-8)=(-2±√13,-8)=(-2±3.6,-8)=(-5.6,-8) and (1.6,-8) \n" ); document.write( "
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