document.write( "Question 17407: How many four letter words can be formed with the word MANAGEMENT?
\n" ); document.write( "In the question use the technique where order matters.
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Algebra.Com's Answer #363274 by crazymaths(1)\"\" \"About 
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Question:-How many four letter words can be formed with the word MANAGEMENT?\r
\n" ); document.write( "\n" ); document.write( "In the question use the technique where order matters.\r
\n" ); document.write( "\n" ); document.write( "This is an example of Distinct Permutation.\r
\n" ); document.write( "\n" ); document.write( "Ok, the word \"MANAGEMENT' contains of 8vowels and 2consonants.\r
\n" ); document.write( "\n" ); document.write( "The letters repeating are \"A\" = 2 times, \"M\" = 2 times, \"N\" = 2 times, \"E\" = 2 times.\r
\n" ); document.write( "\n" ); document.write( "Conditions taken into account for solving :-\r
\n" ); document.write( "\n" ); document.write( "1> If repetition is allowed, then\r
\n" ); document.write( "\n" ); document.write( " 10 P 4 --------------> As four letter word is to be formed by 10 letter word
\n" ); document.write( " Which is 10*9*8*7=5040
\n" ); document.write( " Answer 1:- 5040 -----> If repetition is allowed.\r
\n" ); document.write( "\n" ); document.write( "2> If repetition is NOT allowed, then\r
\n" ); document.write( "\n" ); document.write( " 10 P 4 / 2! * 2! * 2! *2! ----------> Eliminating the repeating elements, A, M, N & E respectively
\n" ); document.write( " (2! = 2*1) E.g (5!=5*4*3*2*1) So (2!*2!*2!*2!=2*1 *2*1 *2*1 *2*1 = 16)
\n" ); document.write( " Therefore, 5040/16\r
\n" ); document.write( "\n" ); document.write( " Answer 2:- 315-----> If repetition is now allowed.\r
\n" ); document.write( "\n" ); document.write( "Therefore. there are 315 four letter words that can be formed by letter \"M A N A G E M E N T '.
\n" ); document.write( "Crazymaths,
\n" ); document.write( "Cheers, hope this helps you !!!!!!!!!!!!!
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