document.write( "Question 558842: What's the answer to x^+5x+2 \n" ); document.write( "
Algebra.Com's Answer #363266 by Theo(13342)\"\" \"About 
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x^2 + 5x + 2 is your equation.
\n" ); document.write( "that doesn't factor, so use the quadratic formula.
\n" ); document.write( "set the equation equal to 0 to get:
\n" ); document.write( "x^2 + 5x + 2 = 0
\n" ); document.write( "a = 1
\n" ); document.write( "b = 5
\n" ); document.write( "c = 2
\n" ); document.write( "x = (-b +/- sqrt(b^2-4ac))/(2a) becomes:
\n" ); document.write( "x = (-5 +/- sqrt(5^2-4*1*2))/(2*1) which becomes:
\n" ); document.write( "x = (-5 +/- sqrt(25-8))/(2*1) which becomes:
\n" ); document.write( "x = (-5 +/- sqrt(17))/(2*1) which becomes:
\n" ); document.write( "x = (-5 +/- 4.123105626)/2
\n" ); document.write( "x is either equal to -.438447187 or -4.561552813
\n" ); document.write( "you can confirm by substituting these values for x in the equation x^2 + 5x + 2 = 0 to see if those equations hold true.\r
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