document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=558883>Question 558883</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two trains travel in opposite directions from the same station at rates differing by 20 kph. in two hours they will be 160 km apart </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363251 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A speed =x<BR>\n" );
document.write( "Train B speed = x+20\r<BR>\n" );
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document.write( "they are moving away<BR>\n" );
document.write( "so add up speeds<BR>\n" );
document.write( "combined speed = 2x+20\r<BR>\n" );
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document.write( "distance = 160<BR>\n" );
document.write( "time = 2hours<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "2=160/(2x+20)<BR>\n" );
document.write( "2(2x+20)=160<BR>\n" );
document.write( "4x+40=160<BR>\n" );
document.write( "4x=120<BR>\n" );
document.write( "/4<BR>\n" );
document.write( "x=30 mph\r<BR>\n" );
document.write( "\n" );
document.write( "The speeds are 30 & 50 mph </SPAN>\n" );
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