document.write( "Question 54072This question is from textbook Algebra and Trigonometry
\n" ); document.write( ": Please help me with this problem:
\n" ); document.write( "The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it be shortened to achieve a 1 second period? \n" ); document.write( "
Algebra.Com's Answer #36325 by stanbon(75887)\"\" \"About 
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The period of a simple pendulum is directly proportional to the square root of its length.
\n" ); document.write( "This means Period = ksqrt(length)
\n" ); document.write( "You need to find \"k\".
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\n" ); document.write( "If a pendulum has a length of 6 feet and a period of 2 seconds
\n" ); document.write( "This means 2=ksqrt6
\n" ); document.write( "Then k=2/sqrt6
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\n" ); document.write( "So now we know the formula for a perdulum is:
\n" ); document.write( "P=(2/sqrt6)sqrt(length)
\n" ); document.write( "P=2sqrt(length/6)
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\n" ); document.write( "To what length should it be shortened to achieve a 1 second period?
\n" ); document.write( "Using that formula you get:
\n" ); document.write( "1=2sqrt(length/6)
\n" ); document.write( "sqrt(length/6)=1/2
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "(length/6)=1/4
\n" ); document.write( "length = 3/2 ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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