document.write( "Question 558851: in a chemistry class, 15L of a 13% alchohol solution must be mixed with a 30% solution to get a 15% solution. how many liters of the 30% solution are needed? \n" ); document.write( "
Algebra.Com's Answer #363237 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
percent ---------------- quantity
\n" ); document.write( "Alcohol type I 13 ---------------- 15 liters
\n" ); document.write( "alcohol type II 30 ---------------- x liters
\n" ); document.write( "Mixture 15 ---------------- 20 + x liters
\n" ); document.write( "
\n" ); document.write( "13*15+30x=15(20 +x)
\n" ); document.write( "195+30x =300+15x
\n" ); document.write( "30x-15x=300-195
\n" ); document.write( "15 x = 105
\n" ); document.write( "/ 15
\n" ); document.write( "x= 7 liters of alcohol type II
\n" ); document.write( "
\n" ); document.write( "
\n" );