document.write( "Question 557415: log8x+log64(x+2)=1 \n" ); document.write( "

Algebra.Com's Answer #363227 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
log8x+log64(x+2)=1
\n" ); document.write( "log8x+log64+log(x+2)=1
\n" ); document.write( "log8x+log(x+2)=1-log64=-0.80617997
\n" ); document.write( "log[(8x)(x+2)]=-0.80617997
\n" ); document.write( "convert to exponential form
\n" ); document.write( "10^-0.80617997=8x*(x+2)
\n" ); document.write( "0.15625=8x^2+16x
\n" ); document.write( "8x^2+16x-.15625=0
\n" ); document.write( "solve by quadratic formula:
\n" ); document.write( "x=-2.00972(reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=0.0097184
\n" ); document.write( "Check:
\n" ); document.write( "log 8x=-1.10931524
\n" ); document.write( "log64(x+2)=log(64*2.0097184)=2.10931518
\n" ); document.write( "log8x+log64(x+2)=-1.10931524+2.10931518=0.99999994≈1
\n" ); document.write( "anybody know an easier way? \n" ); document.write( "

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