document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=558833>Question 558833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 12 cm square is cut along a diagonal to create two right triangles. Find the perimeter of each triangle to the nearest tenth of a centimeters. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363222 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363222\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the diagonal of square bisects the square\r<BR>\n" );
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document.write( "the diagonal is the hypotenuse of triangle with the sides as leg1 & leg2\r<BR>\n" );
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document.write( "Hypotenuse ^2= leg1^2+leg2^2					<BR>\n" );
document.write( "					<BR>\n" );
document.write( "leg1 = 	12	cm			<BR>\n" );
document.write( "Leg2^2=	12	cm			<BR>\n" );
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document.write( "Hypotenuse^2	12	^2	+	12	^2<BR>\n" );
document.write( "Hypotenuse^2	144	+	144		<BR>\n" );
document.write( "Hypotenuse^2	288				<BR>\n" );
document.write( "take the square root					<BR>\n" );
document.write( "Hypotenuse=	16.97	cm			<BR>\n" );
document.write( "=17 \r<BR>\n" );
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document.write( "Perimeter = 17+12+12= 41 cm </SPAN>\n" );
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