document.write( "Question 558830: A boat on a river travels 50miles downstream in only 5 hours. It takes the same boat 9 hours to travel 18miles upstream. What are the speed of the boat and the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #363221 by mananth(16946)\"\" \"About 
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boat speed= x mph
\n" ); document.write( "current speed= y mph
\n" ); document.write( "with current speed (x+y)
\n" ); document.write( "against current speed (x-y)
\n" ); document.write( "d= 50 downstream
\n" ); document.write( "50 / (x+y) = 5
\n" ); document.write( "divide by 5
\n" ); document.write( "10 / (x+y) = 1
\n" ); document.write( "(x+y) = 10 ............1
\n" ); document.write( "d=18
\n" ); document.write( "18 /(x-y)= 9 against wind
\n" ); document.write( "divide by 9
\n" ); document.write( "2 /(x-y) =
\n" ); document.write( "x-y=2 .............2
\n" ); document.write( "add up (1) & (2)
\n" ); document.write( "2 x = 12
\n" ); document.write( "/ 2
\n" ); document.write( "x= 6 mph speed of boat in still water
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "we get y= 4 mph speed of current
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