document.write( "Question 558830: A boat on a river travels 50miles downstream in only 5 hours. It takes the same boat 9 hours to travel 18miles upstream. What are the speed of the boat and the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #363221 by mananth(16946)![]() ![]() You can put this solution on YOUR website! boat speed= x mph \n" ); document.write( "current speed= y mph \n" ); document.write( "with current speed (x+y) \n" ); document.write( "against current speed (x-y) \n" ); document.write( "d= 50 downstream \n" ); document.write( "50 / (x+y) = 5 \n" ); document.write( "divide by 5 \n" ); document.write( "10 / (x+y) = 1 \n" ); document.write( "(x+y) = 10 ............1 \n" ); document.write( "d=18 \n" ); document.write( "18 /(x-y)= 9 against wind \n" ); document.write( "divide by 9 \n" ); document.write( "2 /(x-y) = \n" ); document.write( "x-y=2 .............2 \n" ); document.write( "add up (1) & (2) \n" ); document.write( "2 x = 12 \n" ); document.write( "/ 2 \n" ); document.write( "x= 6 mph speed of boat in still water \n" ); document.write( "plug value of x in (1) \n" ); document.write( "we get y= 4 mph speed of current \n" ); document.write( " \n" ); document.write( " |