document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=558748>Question 558748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy is 26 years younger than his father. In 3 years time, his age would be a third of the father's age. Find the boy's present age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363216 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> brother's age	x												<BR>\n" );
document.write( "													<BR>\n" );
document.write( "sons age	x												<BR>\n" );
document.write( "fathers age	x+26										<BR>\n" );
document.write( "	3	years later											<BR>\n" );
document.write( "sons age	x+3										<BR>\n" );
document.write( "fathers age	x+26+3	=x+29	\r<BR>\n" );
document.write( "\n" );
document.write( "if son is 1/3 of father's age , father is 3 times sons age		<BR>\n" );
document.write( "fathers age	3	times older											<BR>\n" );
document.write( "x+29=3(x+3)		<BR>\n" );
document.write( "x+29=3x	+9				<BR>\n" );
document.write( "3x-x=29	-9					<BR>\n" );
document.write( "2x=20								<BR>\n" );
document.write( "/2										<BR>\n" );
document.write( "x=10	sons age								<BR>\n" );
document.write( "x	+	26		=	36	years		fathers age			<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );