document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=558821>Question 558821</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of a (n) 90% orange juice drink must be mixed with 16 gallons of a 30% orange juice drink to obtain a mixture that is 50% orange juice? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363210 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	percent	----------------	quantity								<BR>\n" );
document.write( "Orange juice type I	30----------------16	gallons					<BR>\n" );
document.write( "Orange juice type II	90----------------x	gallons					<BR>\n" );
document.write( "Mixture	50----------------20+x	gallons					<BR>\n" );
document.write( "											<BR>\n" );
document.write( "30*16+90x=50(20+x)<BR>\n" );
document.write( "480+90x	=1000+50x			<BR>\n" );
document.write( "90x-50x=1000-480				<BR>\n" );
document.write( "40	x	=	520								<BR>\n" );
document.write( "/	40										<BR>\n" );
document.write( "x=	13	gallons	of 	Orange juice type II							<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );