document.write( "Question 558804: y/(5y+3) = 1/(2y)\r
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Algebra.Com's Answer #363200 by edjones(8007)\"\" \"About 
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y/(5y+3) = 1/(2y)
\n" ); document.write( "y(2y)=5y+3
\n" ); document.write( "2y^2-5y-3=0
\n" ); document.write( "2y^2-6y+y-3=0
\n" ); document.write( "2y(y-3)+1(y-3)=0
\n" ); document.write( "(2y+1)(y-3)=0
\n" ); document.write( "y=3, y=-1/2
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