document.write( "Question 558783: A plane travelled 1320 miles to Houston and back. The trip there was with the wind. It took 10 hours. The trip back was into the wind. It took 15 hours. What is the speed of the plane in still air? What is the speed of the wind? \n" ); document.write( "

Algebra.Com's Answer #363174 by mananth(16946) $\"\"$ $\"About$

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Plane speed= x mph
\n" ); document.write( "wind speed= y mph
\n" ); document.write( "with wind speed= (x+y)
\n" ); document.write( "against wind speed (x-y)
\n" ); document.write( "d= 1320
\n" ); document.write( "1320 / (x+y) = 15
\n" ); document.write( "divide by 15 1
\n" ); document.write( "88 / (x+y) =
\n" ); document.write( "(x+y) = 88
\n" ); document.write( "d= = 1320 ............1
\n" ); document.write( "1320 /(x-y)= 10 against wind
\n" ); document.write( "divide by 10
\n" ); document.write( "132 /(x-y) =
\n" ); document.write( " x - 1 y = 132 .............2
\n" ); document.write( "add up (1) & (2)
\n" ); document.write( "2 x = 220
\n" ); document.write( "/ 2
\n" ); document.write( "x= 110 mph speed of Plane in still air
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "we get y= -22 mph speed of wind
\n" ); document.write( " \n" ); document.write( "

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