document.write( "Question 558747: 1/x = 1/y - 1/z\r
\n" ); document.write( "\n" ); document.write( "solve for z.\r
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\n" ); document.write( "\n" ); document.write( "I think it might me something alone the lines of cross multiplying then working the equation down from there but I'm not sure..
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Algebra.Com's Answer #363152 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
For \"1%2Fx\", \"1%2Fy\", and \"1%2Fz\" to exist, the three denominators have to be different from zero, and so would be their product \"xyz\"
\n" ); document.write( "We can eliminate denominators by ultiplying both sides of the equation times \"xyz\"
\n" ); document.write( "\"xyz%2Fx=xyz%281%2Fy+-+1%2Fz%29\" --> \"yz=xyz%2Fy-xyz%2Fz\" --> \"yz=xz-xy\"
\n" ); document.write( "After getting rid of the denominators, we eant to get all the z's to one side of the equal sign.
\n" ); document.write( "\"yz=xz-xy\" --> \"xz-yz-xy=0\" --> \"%28x-y%29z-xy=0\" --> \"%28x-y%29z=xy\" --> \"z=xy%2F%28x-y%29\"
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